Question

A uniform half meter rule can be balanced at the 29.0cm mark
when a mass 20g is hung from its one end.

a)Draw a diagram of the arrangement.

b)Find the mass of the half meter rule.

c)In which direction would the balancing point shift if 20g mass is shifted inside from its one end?

Answer 1

Answer:

and it acts at the 25 cm mark (centre of gravity).

Now,

Acticlockwise moment = x×4

Clockwise moment = 20×21

In equilibrium,

Anticlockwise moment = Clockwise moment

4x=20×21

x=105 gf.

Thus, the weight of the metre rule is 105gf.

We know, one gf is the force acting on the body of mass 1 grams, thus mass of the body is 105grams.

solution