A uniform ladder of mass 10kg leans against a smooth vertical wall making an angle of 53 degree with it.The other end rests on a rough horizontal force.Find the normal force and the frictional force that the floor exerts on the ladder.
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In the ladder which is of length L there are basically 4 forces which are acting on the ladder.
The weight is denoted as W now we calculate the weight that is W= 10*9.8=98N
In the floor the vertical reaction which is acting upwards is equal to the Weight W
The two couples must be equal we solve for the friction F
W(l/2)sin? = FLcos?
= [w/2]tan?
= {98/2} tan 53o
= 65 N
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Hope this helps you. This still is from hc Verma
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