A uniform meter rule is pivoted at its mid point. a weight of 50gf is suspended at one end of it.where shoul a weight of 100gf be suspended to keep the rule horizontal
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Rule is pivoted at its mid point and a 50 gf (gram force) is suspended at one end.
so, to keep the rule horizontal net moment at the mid point should zero.
let 'a' is the distance from the centre where 100 gf (gram force) is suspended.
50gf × (L/2) = 100gf × a
a = L/4
length of rule is 1 metre. so, a = 0.25m
so, to keep the rule horizontal net moment at the mid point should zero.
let 'a' is the distance from the centre where 100 gf (gram force) is suspended.
50gf × (L/2) = 100gf × a
a = L/4
length of rule is 1 metre. so, a = 0.25m
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