Question

A uniform meter rule is pivoted at the 60 cm mark on its left side . A 6.0 N weight is suspended from its right end at 40 cm away from the pivot , causing the rule to rotate about the pivot. What load should be suspended at 60 cm to the left side to balance the meter​

Answer 1

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Correct option is

B

1.4Nm

Torque due to load =4N×40cm=1.6Nm

Torque due to weight of the rule =2N×10cm=0.2Nm

Both are in opposite to each other so net torque =1.6−0.2=1.4Nm

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