a uniform meter rule of weight 10 gf is pivoted at its 0 mark what moment of force depresses the rule? explain
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Answered by
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Moment of force =
magnitude of force X perpendicular distance of the line of action of force from the axis of rotation= 50cm X 10gf = 500 gf cm (ans)
magnitude of force X perpendicular distance of the line of action of force from the axis of rotation= 50cm X 10gf = 500 gf cm (ans)
yas5:
can u please explain
can u telo me how cant the meter rule made be horizontal by appling a least force
Answered by
1
Answer:
500 gf
Explanation:
50 x 100=500 gf
Hope that helps.
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