Question

If p=-4 and q=1 then find the value

Answer 1

1 + p2 + q2
= 1 + 16 +1
=18

2p2+ 7pq+ q2
=32 - 28 + 1
= 5

Answer 2

p=-4 q=1
so
$1 + {p}^{2} + {q}^{2}$
$= 1 + {( - 4)}^{2} + {1}^{2}$
$1 + 16 + 1$
=18
$2 {p}^{2} + 7pq + {q}^{2}$
$= 2 {( - 4)}^{2} + 7( - 4)(1) + {1}^{2}$
$2(16) - 28 + 1$
$32 - 28 + 1 = 4 + 1 = 5$