Question

A uniform meter rule of weight 50gf is balanced at 40cm mark, when a weight of 100gf is suspended at 5cm mark . where must a weight of 60gf be suspended to balance the meter rule​

Answer 1

Let a wt. of 80gf be placed at a distance x from 40cm mark.

Clock wise moments = Anticlock wise moment

(80 × x) + 50 × (50 – 40) = 100 × (40 – 5)

80x +500 = 3500

80x = 3500 – 500 = 3000

x = 3000/80 = 37.5cm

∴ A is at 40 + 37.5 = 77.5cm mark