Question

a uniform meter sacale is balanced at 40 cm mark, when wight of 25 gf and 10 gf are suspended at 5 cm mark and 75 cm mark respectively.calculate weight of the meter scale

Answer 1

balance point = b= 40
W1= 25gf at distance d1 = 5cm
W2= 10gf at distance d2 = 75cm

now the weiht of meter rod:
=W x b + w1b1 + w2b2
=W x 50 + 25 x 5 + 10 x 75
= (W+25+10)40 
10W = 525 
W = 52.5 gf 

Answer 2

Answer:

balance point = b= 40

W1= 25gf at distance d1 = 5cm

W2= 10gf at distance d2 = 75cm

now the weiht of meter rod:

=W x b + w1b1 + w2b2

=W x 50 + 25 x 5 + 10 x 75

= (W+25+10)40  

10W = 525  

W = 52.5 gf  

Explanation: