Question

A uniform meter scale weighing 50gf is pivoted at 60cm . Two forces 15gf and 100gf are suspended on it . If 15gf is at 10cm where is 100gf suspended on the meter scale?
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Answer 1

Answer:

sorry but l don't know

really sorry

Answer 2

Explanation:

100 y = 50×10+15 ×50

= 1250

y= 12.5 CM

so position of 100 gf is

100- 12.5

at 87.5 cm