Question

a uniform metre rule is pivoted at its mid point .A weight of 50gf is suspended at one end of it where should a weight of 100go be suspended to keep the rule horizontal

Answer 1

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l. x cm fulcrum. 50cm
100gf 50gf

100*x=50*50

x=50*50/100

x=25 cm

Ans : 100gf of load should be suspended at 25 cm of Mark from the fulcrum

HOPE THIS HELPS U

Answer 2

it should be suspended at 1/4th to the distance of the length from the other side