A uniform metre rule of weight 10 gf is pivoted at its 0 mark.
i) What moment of force depresses the rule?
ii) How can it be made horizontal by applying the least force?
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The given data suggests that the uniform meter rule of weight 10gf is pivoted at zero mark. Solution: So the moment of force is given by the product of magnitude of force and perpendicular distance corresponding to the force action line in relation to rotational axis. Thereby the moment of force .
Answered by
3
Answer:
The given data suggests that the uniform meter rule of weight 10gf is pivoted at zero mark. Solution: So the moment of force is given by the product of magnitude of force and perpendicular distance corresponding to the force action line in relation to rotational axis. Thereby the moment of force .
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