A uniform metre scale of mass 2kg is
suspended from one end. If it is displaced
through an angle 60° from the vertical, the
increase in its potential energy is,
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Explanation:
since (60)=X/(0.5)
X=1/2×sin(60)
X=1/2×√3/2
=√3/4
potential energy - mgh
=2×10×√3/4
=5√3J
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