a uniform metre scale of weight 20 g is supported on a edge placed at 60cm mark. if a weight of 30g is suspended at 15cm mark,where should a weight of 200g be suspended to balance the scale?
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1
Answer:
67.75
Explanation:
1) Apply the law of moments.
(ii) Let the weight of 200 gf be suspended at distance 'x'.
(iii) moment of force = force × perpendicular distance of force from the wedge.
(iv) Find anti-clockwise and clockwise moments.
(v) Principle of moments : sum of anti-clockwise moments = sum of clockwise moments.
(vi) 67.75 cm mark on scale.
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0
Answer:67.75cm
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