A uniform
metre stick weighing 0.24 kg. can be balanced by a 0.24 kg. wt placed at 100
cm. mark, if the support is placed at the reading marked at
60 cm. 75 cm. 40 cm. 50 cm.
Answers
Answered by
1
0------------------50------------------100
<--------->
x
let at a distance x it can be balanced
since the center of mass of stick at center
for equilibrium of meter stick torque of both side should be equal
0.24x = 0.24(50 - x)
x = 25 cm.
distance = 50 + 25 = 75 cm.
hence option (b ) is correct
<--------->
x
let at a distance x it can be balanced
since the center of mass of stick at center
for equilibrium of meter stick torque of both side should be equal
0.24x = 0.24(50 - x)
x = 25 cm.
distance = 50 + 25 = 75 cm.
hence option (b ) is correct
Answered by
1
The answer is option 2-75 cm
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