Question

A uniform
metre stick weighing 0.24 kg. can be balanced by a 0.24 kg. wt placed at 100
cm. mark, if the support is placed at the reading marked at


60 cm.                         75 cm.                                     40 cm.                         50 cm.

Answer 1

0------------------50------------------100
                    <--------->
                          x
let at a distance x it can be balanced
since the center of mass of stick at center
for equilibrium of meter stick torque of both side should be equal
0.24x  = 0.24(50 - x)
x = 25 cm.
distance = 50 + 25 = 75 cm.
hence option (b ) is correct

Answer 2

The answer is option 2-75 cm