Question

A uniform rectangular marble slab is 3.4m long and 2.0m wide . it has a mass of 180kg . if it is originally lying on a flat ground , the work required to stand on it on an end is​

Answer 1

Answer:

Step-by-step explanation:

WORK DONE:

When some external force acting on the body for moving it to some distance is called work done. It is the vector quantity and the SI unit is Joules. For lifting the object, if the force is applied to the center of mass of the object, minimum work has to be done for lifting purposes.

SOLUTION:

Given data:

   Length of the slab (l)=3.4m

   Width of the slab (b)=2m

   Mass of the rectangular slab (m)=180kg

When the slab stands on shorter end (2m) , the height of center of mass of shorter side will be

h=b/2

h=1m

The expression for the work done needed to stand the slab is

W=F×h

Substituting the values in above expression we get

W=mg×h

W=180×9.81×1

W=1765.8J

Therefore the work done needed to stand the rectangular slab is 1765.8J