Question

A uniform rod of length 1m and mass 100 g is pivoted at one end
and is hanging vertically. It is displaced through 600 from the
vertical. The increase in its potential energy is(g = 10ms)
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Answer 1

Answer:

At mean postion the total energy would be =>

mgl/2 + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2

Hence the Total ENERGY would be => root(3)*0.5*10*2/4 => 5root(3) J