A uniform rod of length 4 m and mass
2v2 kg revolves with constant angular
velocity w about a vertical axis through a
smooth joint A at one extremity of the rod
so that it describes a cone of semi
vertical angle 53° as shown in the figure.
choose the INCORRECT statement(s).
(g=10m/s?)
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Answer:The value of angular velocity `omega` is `2.5rad//s`
The angle between hinge reaction at point `A` and vertical axis `AC` is `45^(@)`
The magnitude of hinge reaction at point `A` is `40N`
The angular momentum of the rod is constant.
Solution :
`F=2xx(mu_(0)I_(1))/(2piR)xxI_(2)l=(2xx2xx10^(-7)xx50xx20xx0.50)/(0.25)=8xx10^(-4)N`
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