Question

A uniform rod of length l and mass m is hung from two strings

Answer 1

The required formula,

Torque = Moment of inertia x angular momentum

τ = I x α

Here I = (1/12).m.L²

and τ = mg (L/2)

Thus, α = τ / I

or, α = mg(L/2) / (1/12)m.L²

or, α = 6.g / L

I answered based on the most possible way the question should be, which is to deduct the angular momentum of the rod when one string is cut.

Therefore, the angular momentum is 6g / L.