Question

A uniform rod of mass 6m and length 6l is bent to make an equilateral hexagon. Its m.I. About an axis passing through the centre of mass and perpendicular to the plane of hexagon is:

Answer 1

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The only difference is that, Length of each side of Hexagon is 'L' instead of '2L'.

Then, Moment of Inertia =
$20M (\frac{L}{2})^2 = 5 ML^2$ .

Hence. Our Required answer is
$5ML^2$ .