A uniform rope of length 12 and mass 6 kg hangs vertically from a rigid support a block of mass 2 kg is attached to the free end of the rope i transferred files of wavelength 0.06 m is produced at the lower end of the rope what is the wavelength of the balls when it reaches the top of the rope
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Given:
Rope length = 12
Rope mass = 6
Block mass = 2 kg
Wavelength = 0.06 m
To find:
The wavelength of the balls when it reaches the top of the rope.
Solution:
By formula,
Velocity = √T / m
Where,
T - tension
m - mass per unit length.
By law,
Tension ∝ Velocity
As the tension of the rope increases, the velocity of the rope also increases.
Therefore,
Velocity of the rope / velocity of the blovk = √Tension in the rope / √Tension in the blovk
√2 * 9.8 / 8 * 9.8
1/2
As the frequency is same,
Wavelength is calculated by,
∴ Wavelength of the balls = 2 * Wavelength of the files
2 x 0.06
0.12 m
Hence, the wavelength of the balls when it reaches the top of the rope is 0.12 m.
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