Question

A uniform solid sphere of radius r has a hole of r/2 drilled inside it. one end of the hole is at the center of the sphere while the other is at the boundary locate center of mass​

Answer 1

Answer:

sorry I didn't understand the question please check it and let me know....thanks...

Answer 2

The center of mass of the sphere can be calculated as follows :

• Consider the original sphere( with no hole) of radius r having a postive mass M.

• Consider the drilled sphere of radius r/2 having a negative mass -M'.

• Therefore , the Center of Mass of the new body can be represented as:

$r = \frac{M.r-(M').\frac{r}{2} }{M+(-M')}$

$r=\frac{M.r-M'.\frac{r}{2} }{M-M'}$

$r=\frac{2M.r-M'r}{2(M-M')\\}$

• Hence the center of mass of the sphere is   $r=\frac{2M.r-M'r}{2(M-M')\\}$