Question

A uniform spherical shell of mass M and radius R is placed at a distance R
from a uniform rod of mass M and length R. The force of interaction between
the two, is
​

Answer 1

The gravitational force of interaction is given as$F=6.67\times 10^{-11}\times \frac{M^2}{4R^2}$ always attractive in nature

Explanation:

From the given figure we can see that the given geometries are symmetrical and the axis of the rod lies along the radius of the sphere.

The gravitational force acting in the case is:

$F=G\times \frac{M.M}{(2R)^2}$

$F=6.67\times 10^{-11}\times \frac{M^2}{4R^2}$

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TOPIC: gravitational force

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