Question

A uniform thin circular ring of mass M and radius R is bent 8-shaped planar loop. Assuming
the two smaller loops to be identical, what is the moment of inertia of this system about an
axis passing through their common point and perpendicular to the plane?​

Answer 1

Answer:

this is answer. I think

Explanation:

Two rings of same radius and mass are placed such that their centres are at a common point and their planes are perpendicular to each other. The moment of inertia of the system about an axis passing through the centre and perpendicular to the plane of one of the rings is (mass the ring =m, radius =r)