Question

A uniform thin rod of length 1m and mass
3kg is attached to a uniform thin
circular disc of radius 30cm and mass
1kg at its centre perpendicular to its
plane. The centre of mass of the
combination from the centre of disc is​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf X_{COM}=0.375m}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Lenght of rod = 1m

its half Lenght will be = 0.5 m

• Mass ($\sf{m_1}$)=3kg

• Mass ($\sf{m_2}$)=1kg

$\large\underline\pink{\sf To\:Find: }$

• Centre of mass of the
• combination from the centre of disc is ($\sf{X_{COM}}$)=?

━━━━━━━━━━━━━━━━━━━━━━━━

From above Fig.

we can say that :

$\large{♡}$$\large{\boxed{\sf X_{COM}=\frac{m_1d}{m_1+m_2}}}$

$\large\implies{\sf \frac{3×0.5}{4} }$

$\large\implies{\sf 0.375m }$

$\huge\red{♡}$$\large\red{\boxed{\sf X_{COM}=0.375m}}$

Hence ,

Centre of mass of the combination from the centre of disc is 0.375m