a uniform wire of resistance 100ohm is melted and recast into wire of length double that of the original what would be the resistance of new wire
Answers
Answered by
3
Answer:
400Ω
Explanation:
R=ρl/A ρ is a constant.
volume remains same. so, l*A=2l*A1⇒new area A1=A/2⇒R1=ρl1/A1
R1=4*R=4*100=400Ω
Answered by
0
Answer:1000000
Explanation:
Similar questions