Question

A uniform wire of resistance 40 ohm is bent to form a sqare. What is the effective resistance between any two diagonally opposite corners of the square

Answer 1

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▶A uniform wire of resistance is bent in the form of a square !

▶ Each side of the square has a resistance of 10 ohm.

$\: R_1=R_2=R_3 =R_4 = 10 \: ohm$

➡We need to find the effective resistance between any two diagonally opposite corners of the square.

$\: R_1, R_4 \: \: ; \: \: \: R_2 ,R_3$

These are in series.

$\: R_s1 = R_1 + R_4 = 10 + 10 = 20$

$R_s2 = R_2 + R_3 = 10 + 10 = 20$

$\: R_s1 ; R_s2$

These are in parallel

$\: R_p = \frac{ R_s1 \times R_s2}{R_s1 + R_s2}$

$\: R_p = \: \frac{20 \times 20}{20 + 20}$

$R_p = \frac{400}{40}$

$R_p = \: 10 \: ohm \:$

Therefore ,the effective resistance between the diagonally opposite corners of the square is 10 ohm.

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Answer 2

Answer:

Here is the answer...