A uniformly accelerated body travelling along a straight line with an initial velocity of 2 m/s passes over 24 m from start in 3 seconds. Calculate the acceleration and the velocity it will acquire when it has passed over 4 m from the start
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Explanation:
Given:-
u(initial velocity)- 2m/s
time- 3sec
distance - 24m/s
s=ut+1/2at^2
24=2×3+1/2a(3)2
24=6+1/2a*9
24=6+9/2a
24-6=9/2a
18=9/2a
18*2/9=a
a=4m/s
v=u+at
v=2+4*3
v=2+12=14m/s
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