a uniformly accelerated car is found to possess the velocity is 12.5 M per second and 135 km per hour at two different places in its path if the car takes 10 minutes to travel between these places find the distance between them
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u=12.5 m/s
v=135km/h=75/2=37.5m/s
t=10sec
v=u+at
a=v-u/t =37.5-12.5/10=25/10=2.5m/s^2
s=ut+1/2at^2
=12.5×10+1/2×2.5×10×10
=125+250×5
=125+1250
=1375 m
v=135km/h=75/2=37.5m/s
t=10sec
v=u+at
a=v-u/t =37.5-12.5/10=25/10=2.5m/s^2
s=ut+1/2at^2
=12.5×10+1/2×2.5×10×10
=125+250×5
=125+1250
=1375 m
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