A uniformly charged conducting sphere of 2.8 m in diameter has a surface charge density of 100 microcoulomb metres square find the charge on the sphere what is the total electric flux leaving the surface of the sphere
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As per the Gauss' law, the total flux passing through a gaussian surface is equal to the 1/ε times the charge enclosed with the gaussian surface.
Mathematically,
Φ = q/ε
To find out the charge, we use the surface charge density, б
Given, б = 100μC/
The charge carried by the Conductor = Charge density * Surface area of conductor
=
= 2.464 mC
So, Flux pasing = q/ε
= 2.464*10^-3/ε
=278.8M Vm
Hope it helped you!
Don't forget to give Brainliest Answer!
Mathematically,
Φ = q/ε
To find out the charge, we use the surface charge density, б
Given, б = 100μC/
The charge carried by the Conductor = Charge density * Surface area of conductor
=
= 2.464 mC
So, Flux pasing = q/ε
= 2.464*10^-3/ε
=278.8M Vm
Hope it helped you!
Don't forget to give Brainliest Answer!
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