Question

A uniformly charged non-conducting hollow sphere of radius and angular speed and rough horizontal surface

Answer 1

$\mathfrak{\huge{\red{\underline{\underline{AnswEr :}}}}}$

$\large \boxed{{ \frac{M}{L} = \frac{Q}{2m} }}$

Where M is magnetic moment , L is angular momentum of body , Q is the charge on body and m is the mass of body .

Now, L = Iω

Where I is moment of inertia and ω is angular velocity

for non-conducting solid sphere moment of inertia about it diameter

$\large{I = \frac{2}{5}m {r}^{2} }$

where r is the radius of circle

So, I = 2/5 m₀R²

⇒ L = Iω = 2/5m₀R²ω , use it above formula

M/L = Q/2m₀

M = Q/2m₀ × L = Q/2m₀ × 2/5m₀R²ω = 1/5QωR²

Hence, magnetic moment = 1/5QωR²

Answer 2

A uniformly charged non-conducting hollow sphere of radius and angular speed and rough horizontal surface

M/L=Q/2M