A triangle with sides 42cm 34cm and 20 cm.The biggest side is joint with the the height . Find heigt by heron formula
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Semiperimeter (s) = (42 + 34 + 20 ) / 2
So it is = 96 / 2 = 48 cm.
Using herons formula = (√s )(√s-a )(√s-b) (√s-c)
By substituting s and a , b , c i.e the given sides.
We have √48 × √6 × √14 × √28
So √ (4 × 6 × 2) × √6 × √(7 × 2) × √(7 × 4)
Simplifying the numbers we have area = 4 × 6 × 2 × 7 = 336 cm ²
Hence area is 336 cm²
Now height corresponding to longest side implies that base is 42 cm and area remains same
So area of triangle is 1/ 2 b × h
336 = 1/ 2 × 42 × H
HENCE H = 16 cm
So Height is 16 cm.
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SOLUTION
Given,
In ∆ with sides
42cm
34cm
20cm
Side= 42+34+20/2
=) 48cm
√s(s-a)(s-b)(s-c)
=)√48(48-42)(48-34)(48-20)
=)√48× 6× 14× 28
=) √112896
=) 336cm^2
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