Computer Science, asked by Anonymous, 11 months ago

A uniformly charged ring of radius 3a and total charge q is placed in xy-plane centered at origin. A point charge q is moving towards the ring along the z-axis and has speed v at z = 4a. The minimum value of v such that it crosses the origin is:
(A) √(2/m)(1/5 . q²/4π∈₀a)¹/²
(B) √(2/m)(1/15 . q²/4π∈₀a)¹/²
(C) √(2/m)(4/15 . q²/4π∈₀a)¹/²
(D) √(2/m)(2/15 . q²/4π∈₀a)¹/²​

Answers

Answered by manuel56
1

Answer:

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Answered by Mansi4946
1

Explanation:

A 2m−−√(115q24πε0a)1/2

B2m−−√(215q24πε0a)1/2

C2m−−√(215q23πε0a)1/2

D2m−−√(15q24πε0a)1/2

hope it helps

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