Question

A uranium 235 reactor takes 30 days then rate of fisiion

Answer 1

Answer:

No of mole of uranium 235 in 2 kg = 2*1000/235= 8.51Each fission gives 185 Mev which is 185 × 1.60× 10^-13 joules E = 296 × 10^-13 JOne mole gives 6.023×10^23 × E = 1.78×10^13 JTherefore total energy released with 2 kg U-235= 8.51×1.78×10^13 = 1.517×10^14 J. Power = energy/ time.Since this energy is released over 30 days time = 30×24×60×60= 2592000sHence power output = 1.517×10^14/2.592×10^6 W =5.85×10^7 W

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Explanation:

Answer 2

Answer:

No of mole of uranium 235 in 2 kg = 2*1000/235= 8.51Each fission gives 185 Mev which is 185 × 1.60× 10^-13 joules E = 296 × 10^-13 JOne mole gives 6.023×10^23 × E = 1.78×10^13 JTherefore total energy released with 2 kg U-235= 8.51×1.78×10^13 = 1.517×10^14 J. Power = energy/ time.Since this energy is released over 30 days time = 30×24×60×60= 2592000sHence power output = 1.517×10^14/2.592×10^6 W =5.85×10^7 W

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Explanation: