Physics, asked by Shreeyaharidas8927, 1 year ago

A vaccum cleaner utilizes 36kJ of energy in half hour.what is it's power?

Answers

Answered by parakhcmd
19

36 kj given energy

so, total energy in joules will be=36000

now power = work/time

given time=30 mins=30*60=1800 secs

power=36000/1800=20 j/s

Answered by Percyjackson101
6

We know that

Power=Work/Time

Power=36.1000/1200

36000/1800

20 watt

Hope it helps


Percyjackson101: Pls note it is 36.1000/1800 not 1200
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