Question

A vampire enters a town and bites 2 person every night. the bitten 2 persons grows in to two big vampires and bites 4 persons the next night. these 4 vampires bites 6 people the next night and the 6 bites 8 and so on.......how many vampires will be there on the 5th night?

Answer 1

so the whole thing is an arithmetic progression
a=2
d=2

$a(5) = 2 + 4 \times 2$
a(5)=10
there will be 10 vampires in the fifth night


(please mark this as the brainliest answer!)

Answer 2

Number of person bitten 1st=2
Number of person bitten the next night =4 Number of person bitten the next night =6
Number of person bitten the next night =8
Number of person bitten the next night =10
Number of person bitten on the fifth night
=2+4+6+8+10
=30
Therefore Number of person bitten on the fifth night is 30