Question

A varies directly as the square of B and A=8 when B=2 find A when B=7

Answer 1

Answer:

Step-by-step explanation:

Given A directly proportional to B

A∝B²;

Now there are two conditions

CONDITION 1:

A=KB²;

Where K is constant;

but according to given statement A=8,B=2;

then 8=K2²;

now K=2;

if A =0;then B is also 0 as given it is directly proportional then k multiply with 0 is 0 no solution at all, which overcome in by condition 2 ;

CONDITION 2:

A=B² +K;

This is the valid equation

8=2²+k(now k=4)

given B=7

A=7²+4=53;