Question

a varies directly proportional to b and inversely proportional to c a is 12 when b is 6and c is 2 what is the value of a when b is 12 and c is 3​

Answer 1

Step-by-step explanation:

A is directly proportional to B. So, A=pB (p is a constant)

Again, A is inversely proportional to C. So, A=q/C (q is a constant)

Together, A=kB/C (k=pq)

Now, we can get the value of k as below,

A=6, when B=2 & C=3

So, 6=(k*2)/3,

Then, k=9

Now, when B=8 & C = 6,

A=kB/C

then, A=(9*8)/6,

then, A=12 (Answer)

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A=xB

B=C/y

6=2x

x=3

2=3/y

y=3/2

So when B=8,

8=6/y

y=3/4

As y=x/2

x/2=3/4

x=3/2

S0, A is

3/2*8

12