Question

A vector = 2i + j -k , B vector = i - j- k, c vector 2i+ j +k then value of magnitude of A vector + B vector - C vector is

Answer 1

Hey Atul,

Vector A=2i+j-k

Vector B=i-j-k

Vector C=2i+j+k

Vector A+Vector B-Vector C=(2+1-2)i (1-1-1)j+(-1-1-(+1))k

=i-j-3k

Madnitude=√((1)^2+(-1)^2+(-3)^2 )=√11.


Hope it helps

Answer 2

Answer:

We have three vectors A vector = 2i + j -k , B vector = i - j- k, c vector 2i+ j +k then value of magnitude of A vector + B vector - C vector is $\sqrt{3}$

Explanation:

• A vector is a physical quantity that has both direction and magnitude to represent it completely
• The adding of two vectors A and B

       $A=a_{1} i+a_{2} j+a_{3} k$  and $B=b_{1} i+b_{2} j+b_{3} k$

       the sum of A and B

      $A + B = (a_{1}+ b_{1}) i+(a_{2}+ b_{2}) j+(a_{3} +b_{3}) k$

• The magnitude of a vector in component form, that is $A=ai+bj+ck$ is given by the formula

        $/A/=\sqrt{a^{2} +b^{2} +c^{2} }$

The given vectors are

$A=2i+j-k$

$B=i-j-k$

$C=2i+j+k$

⇒

$A+B-C=(2+1-2)i+(1-1+1)j+(-1-1+1)k=i+j+k$

magnitude is $/A+B-C/=\sqrt{1^{2} +1^{2} +1^{2} } =\sqrt{3}$