Question

A vector √3i + j rotate about its tail through an angle 30° in clock wise direction, then the new
vector is [ ]

a) i + j b) i – j c) 2i d) i + √3j​

Answer 1

Answer:

c) 2i

Step-by-step explanation:

Given,

a = √3i + j

|a| = $\sqrt{(\sqrt{3})^2+(1)^2 }$

|a| = $\sqrt{3+1}$

|a| = √4

|a| = 2

Angle between a and y-axis = 60°

after rotating about 30° in clockwise direction,

new vector = 2i (it will direct toward x axis since 60°+30° = 90°)

(it becomes i in x-axis, and j is y-axis)

Mark as the brainliest....

Answer 2

THE CORRECT ANSWER IS (C)2i

Angle between a and y-axis = 60°

after rotating about 30° in clockwise direction,

new vector = 2i (it will direct toward x axis since 60°+30° = 90°)

(it becomes i in x-axis, and j is y-axis)

#SPJ2