Question

A vector=icap+2jcap+2kcap,B vector=3icap+6jcap+2kcap,then the vector in the direction of A vector and having the same magnitude as modulous of B vector,is​

Answer 1

Answer:

Explanation:

A= 2icap +3 jcap+2kcap

B= 3 Icap + 2 jcap+4 kcap

A×B =(2icap +3 jcap+2kcap)×{3 Icap + 2 jcap+4 kcap)

0+4 kcap-8jcap -9 Icap+0+12 Icap +6jcap-4icap+0

-icap -2 jcap +4kcap

2 -:

B×A={3 Icap + 2 jcap+4 kcap)×(2icap +3 jcap+2kcap) = {0+9kcap-6jcap -4kcap+04 Icap+ 8 jcap-12 Icap +0

5 k cap+2. Jcap-8 Icap

3-:(a+b)× (a-b)

= (5 Icap+5jcap+6 kcap)×(-icap+jcap-2kcap)

(0 +5kcap+10 Icap+5kcap+10 Icap -6 jcap-6icap + 0

= 10 kcap +14 icap - 6 jcap

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Answer 2

I wrote in 2nd step as i bar j bar it's not bar we can write like that also this is correct answer of that question. if it is helpful comment me. it will be helpful in jee /kcet/neet etc exams