Question

A vector inclined at theta to the horizontal and vertical component is Y then magnitude of the vector is

Answer 1

A vector inclined at theta to the horizontal and vertical component is Y then magnitude of the vector is ...

if a vector A inclined at angle $\theta$ with horizontal.

then, horizontal component of vector = |A|cos$\theta$

and vertical component of vector = |A|sin$\theta$

it is given that,

vertical component = Y

so, |A|sin$\theta$ = Y

or, |A| = Y/sin$\theta$

= Ycosec$\theta$

hence magnitude of vector is Ycosec$\theta$

Answer 2

Explanation:

A vector inclined at theta to the horizontal and vertical component is Y then magnitude of the vector is ...

if a vector A inclined at angle thetaθ with horizontal.

then, horizontal component of vector = |A|cos\thetaθ

and vertical component of vector = |A|sinthetaθ

it is given that,

vertical component = Y

so, |A|sinthetaθ = Y

or, |A| = Y/sinthetaθ

= Ycosecthetaθ

hence magnitude of vector is Ycosecthetaθ

hope it will help you

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