Question

a vector of. 10 root2. (10×2^1/2) units in x-y plane

Answer 1

Since the vector is in $\mathrm{X-Y}$ plane, it must not have a component in the $\mathrm{Z}$ direction, hence the coefficient of $k$ is zero.
Thus the vector is $\mathrm{ 10i+10j}$, where the magnitude is given by $\sqrt{ 10^2+10^2}= 10\sqrt{2}$, according to the question.

Answer 2

HLO THERE

YOUR ANSWER IS. 10i+ 10j


here how


the resultant is equal to. whole root of 10square +10square+2×10×10cos90


cos 90. Because X and y axis are perpendicular to each other

cos90 =0
therefore it will take form of whole root of 100+100 =root of 200

that will be 10✓2


hence proved




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