Question

a vector of magnitude 10 has its rectangular components as 8 and 6 along x and y axes . find the angle it makes with these axes

Answer 1

Angle with x-axis = α
Tanα = 6/8 = 3/4
α = 37°

Angle with y-axis = β
Tanβ = 8/6 = 4/3
β = 53°

Answer 2

The angle made with X axis is $\bold{37^{\circ}}$ and with Y axis is $\bold{53^{\circ}}$

Given:

Magnitude of the vector=10 units

Rectangular components of the vector=8 along x axis and 6 along y axis

To find:

We have to find the angle made by the vector at x and y axis

Solution:

Let Angle made with x-axis $= \alpha$

Therefore  

$\ {Tan} \alpha=$$=\frac{6}{8}$

$=\frac{3}{4}$

$\alpha=37^{\circ}$

Let Angle made with y-axis =\beta

$\tan \beta=$$=\frac{8}{6}$

$=\frac{4}{3}$

$\beta=53^{\circ}$

Hence angle made with x axis is $37^{\circ}$and angle made with y axis is $53^{\circ}$.