Question

a vector of magnitude 10 has its rectsngular components as 8 and 6 along x and y axes. find the angle made with these axes​

Answer 1

Answer:

Let the angle between the two vectors be Ø.

Then, Tan (Ø) = Perpendicular/Hypotenuse

Tan Ø = 6/8 = 3/4

Ø = Tan^-1 (3/4)

Ø = 37°

For your information, Remember two particular triangles, one with hypotenuse = 5, perpendicular = 3 and base = 4 (such a triangle will have angle = 37° and another triangle with hypotenuse = 5, perpendicular = 4 and base = 3 (such a triangle will have angle = 53°).