A vector of magnitude 10 has the ractangular components as 8 and 6 along x axis and y axis.find the angles it make with these axes
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Vector is 8i+6j. magnitude of vector =√8^2+6^2=√64+36=10.so10cosA=8and10sinA=6. it makes 53°with X-axis and 37° with Y-axis.
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A Vector is 81 + 6j. Magnitude of Vector = 8Underoute ^2 = Underoute 64+36 = 10. So 10Cos A = 8 And 10 Sin A = 6. It Makes 53Degree with X- Axis And 37Degree With Y- Axis.
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