A vector P makes an angle of 10° and vector Q makes
an angle of 100° with X-axis. The
magnitudes of these vectors are 6m and 8m
The resultant of these vectors is
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Angle between the given vectors is θ = 100°-10° = 90°
Apply the formula
|vectorR| = √( |vectorA|²+|vectorB|²+2|vectorA|•|vectorB|•cosθ )
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