Question

a vector perpendicular to both the vector 2i^ - 3j^ and 3i^ - 2j^ is​

Answer 1

By using dot product we can get the answer

(2i-3j) . (3i-2j)

= (2.3)-(-1) (2.3)

=6+6

=12

Note : i.i=j.j=k.k=1 .....by property of scalar dot product

=

Answer 2

Explanation:

It is given that,

Vector 1, $a=2i-3j$

Vector 2, $b=3i-2j$

Let c is the vector that is perpendicular to both a and b. It can be calculated using the cross product formula as :

$c=a\times b$

$c=(2i-3j)\times (3i-2j)$

$c=0i+0j+5k$

So, the vector that is perpendicular to both a and b is $c=0i+0j+5k$. Hence, this is the required solution.