A VECTOR Q WHICH HAS A MAGNITUDE OF 8 UNITS IS ADDED TO A VECTOR P WHICH LIES ALONG THE X AXIS .THE RESULTANT OF TWO VECTOR LIES ALONG THE Y AXIS .IF THE MAGNITUDE OF THE RESULTANT IS TWICE THAT OF P THEN MAGNITUDE OF P WILL BE
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Let unit vector along x and y axes by i and j respectively
According to question
8 + Bi = 2Bj
8 = 2Bj - Bi
8 = sqrt((2B)^2 + B^2)
8 = sqrt(5B^2)
8 = Bsqrt(5)
B = 8 / sqrt(5)
answer by UrsAnnabelle :)
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