A vector representing a physical quantity is C = si + 3j + 4k, the angle between X-axis and C is
(A) cosâ»Â¹ 3/â(29)
(B) cosâ»Â¹ 4/â(29)
(C) cosâ»Â¹ 5/â(29)
(D) cosâ»Â¹ 2/â(29)
(Note: i, j and k are unit vectors)
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Answer:
Cos⁻¹ (2 / 29)
Explanation:
C = 2i + 3j + 4k
Magnitude = √2² + 3² + 4²
=> Magnitude = √4 + 9 + 16
=> Magnitude = √29
i - x axis
j - y axis
k - z axis
the angle between X-axis and C is = Cos⁻¹( Component of x / Magnitude)
= Cos⁻¹ (2 / 29)
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