Math, asked by neerajkulkarni54, 1 month ago

A vehicle covers a distance of 43.02 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol?

Answers

Answered by TheBrainliestUser
80

Given that:

  • A vehicle covers a distance of 43.02 km in 2.4 litres of petrol.

To Find:

  • How much distance will it cover in one litre of petrol?

Let us assume:

  • It will cover x km in one litre of petrol.

According to the question.

↣ x : 1 = 43.02 : 2.4

↣ x/1 = 43.02/2.4

↣ x = 17.925

Hence,

  • It will cover 17.925 km in one litre of petrol.
Answered by MяMαgıcıαη
149

\large\underline{\mathcal{\blue{GIVEN}}}

\:

  • A vehicle covers a distance of 43.02 km in 2.4 litres of petrol.

\:

\large\underline{\mathcal{\pink{TO\:\:FIND}}}

\:

  • How much distance will it cover in one litre of petrol ?

\:

\large\underline{\mathcal{\green{SOLUTION}}}

\\ \dashrightarrow \: \footnotesize\sf Distance\:covered\:in\:one\:litre\:of\:petrol = \dfrac{Distance\:covered\:in\:2.4\:litre\:of\:petrol}{Petrol\:used}

\\ \dashrightarrow \:\footnotesize \sf Distance\:covered\:in\:one\:litre\:of\:petrol = \dfrac{43.02}{2.4}

\\ \dashrightarrow \: \footnotesize\sf Distance\:covered\:in\:one\:litre\:of\:petrol = {\cancel{\dfrac{43.02}{2.4}}}

\:

After cancelling 43.02 with 2.4, we get ::

\\ \dashrightarrow \: \footnotesize\sf \purple{Distance\:covered\:in\:one\:litre\:of\:petrol = 17.925}

\:

\small\therefore\:{\underline{\sf{Distance\:covered\:in\:one\:litre\:of\:petrol = {\textsf{\textbf{17.925\:km.}}}}}}

\:

\large\underline{\mathcal{\orange{LEARN\:\:MORE}}}

\:

  • Distance of any object does not depend on direction of it's motion. It can be defined as path travelled by an object.

  • For example :: If a bike travels south for 20 km and turns to travel north for 5 km, total distance travelled by bike will be 25 km.

  • The distance can't be negative or zero and it is always more than the displacement of the object.

  • Distance is a scalar quantity.

  • Formula that we can use to calculate distance :: Distance = Speed × Time.

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